3n+15=2(n+2)+n=4

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Solution for 3n+15=2(n+2)+n=4 equation: 



3n+15=2(n+2)+n=4

We move all terms to the left:

3n+15-(2(n+2)+n)=0



We calculate terms in parentheses: -(2(n+2)+n), so:

2(n+2)+n

We add all the numbers together, and all the variables

n+2(n+2)

We multiply parentheses

n+2n+4

We add all the numbers together, and all the variables

3n+4

Back to the equation:

-(3n+4)



We get rid of parentheses

3n-3n-4+15=0

We add all the numbers together, and all the variables

11!=0

There is no solution for this equation

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