3n+12=4(n-1)-n

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Solution for 3n+12=4(n-1)-n equation: 



3n+12=4(n-1)-n

We move all terms to the left:

3n+12-(4(n-1)-n)=0



We calculate terms in parentheses: -(4(n-1)-n), so:

4(n-1)-n

We add all the numbers together, and all the variables

-1n+4(n-1)

We multiply parentheses

-1n+4n-4

We add all the numbers together, and all the variables

3n-4

Back to the equation:

-(3n-4)



We get rid of parentheses

3n-3n+4+12=0

We add all the numbers together, and all the variables

16!=0

There is no solution for this equation

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