3n*3n=38

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Solution for 3n*3n=38 equation:



3n*3n=38
We move all terms to the left:
3n*3n-(38)=0
Wy multiply elements
9n^2-38=0
a = 9; b = 0; c = -38;
Δ = b2-4ac
Δ = 02-4·9·(-38)
Δ = 1368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1368}=\sqrt{36*38}=\sqrt{36}*\sqrt{38}=6\sqrt{38}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{38}}{2*9}=\frac{0-6\sqrt{38}}{18} =-\frac{6\sqrt{38}}{18} =-\frac{\sqrt{38}}{3} $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{38}}{2*9}=\frac{0+6\sqrt{38}}{18} =\frac{6\sqrt{38}}{18} =\frac{\sqrt{38}}{3} $

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