3m=(m-5+12)

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Solution for 3m=(m-5+12) equation: 



3m=(m-5+12)

We move all terms to the left:

3m-((m-5+12))=0

We add all the numbers together, and all the variables

3m-((m+7))=0



We calculate terms in parentheses: -((m+7)), so:

(m+7)

We get rid of parentheses

m+7

Back to the equation:

-(m+7)



We get rid of parentheses

3m-m-7=0

We add all the numbers together, and all the variables

2m-7=0

We move all terms containing m to the left, all other terms to the right

2m=7

m=7/2

m=3+1/2

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