If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3m^2-34m-24=0
a = 3; b = -34; c = -24;
Δ = b2-4ac
Δ = -342-4·3·(-24)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-38}{2*3}=\frac{-4}{6} =-2/3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+38}{2*3}=\frac{72}{6} =12 $
| 6x+39x-8=9(5x+10 | | 6(5-f)=48 | | 10c+19=2c+11 | | 6(5-f)=488 | | 1/5d+1/8=2 | | 1/6x1/6x1/6=1/6x3 | | (x+5)(x=3) | | 5(2x)-2.5(x+1)+25=0 | | -6x+9=51- | | 45-18=x*(x-x) | | 7(4+n)=84 | | 5²x+¹-2.5x+¹+25=0 | | x2+15x+39=0 | | x+15=4x-30 | | 3k=19 | | 6p-2-3p=16,p | | 5/4(4x-10)=15/2 | | -4y^3-2y+5=0 | | 10x+5=(2x-3)+9 | | 8=-3x+29 | | 15+r/3=-9 | | 4(z+5)=32. | | 40=12m=460 | | 5y+8-2y=4+2y+2 | | 21=-3/4(x-2) | | 9x+12=-132 | | 5x=4=8+5x | | t=27 | | -4x+10=~5x+18 | | 4r+1=8-5r | | 10=3/5d | | 1/2(2/3y+1/3)=-1/2(y-5/2) |