3m2+87=675

Solution for 3m2+87=675 equation:

3m^2+87=675

We move all terms to the left:

3m^2+87-(675)=0

We add all the numbers together, and all the variables

3m^2-588=0

a = 3; b = 0; c = -588;
Δ = b2-4ac
Δ = 02-4·3·(-588)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*3}=\frac{-84}{6}
=-14
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*3}=\frac{84}{6}
=14
$