If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3m^2+25m+8=0
a = 3; b = 25; c = +8;
Δ = b2-4ac
Δ = 252-4·3·8
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-23}{2*3}=\frac{-48}{6} =-8 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+23}{2*3}=\frac{-2}{6} =-1/3 $
| 1/4x+7=4(x-2) | | 12h-3h+-5=-14 | | 3v+3=-13+7v | | z2+4z=0 | | -37/8+v=-71/8 | | 2(x+1)=-2(x-5) | | 6x-3+5x+1=2x-6+3-4x | | 2c2-13c+20=0 | | 0.08x+0.12(x+500)=180 | | 2-m=-m+3 | | 2(s+22)=5(s+2) | | 10x/4=80 | | x+2+2x+1=90 | | X×x+24x+144=0 | | 5,6-4x=11.2-2x | | -7d+-13d+7=-13 | | 10x/4=0 | | 1/5g=5 | | 5r+45/20=5r-45/5 | | 5x-15x=-300 | | 2x+1+43=180 | | 2x+16=2x+17 | | t2+16t+63=0 | | 2(x+1)=2(x-5) | | 3(4n+3)-3=-3(-4n-2) | | 7n-2(3n+)=-5+9 | | 2x+11+121=180 | | -12m-2=18-2m | | 2x+11+121=280 | | 7n-18=6 | | 3+2x=24-5x | | -18n+19=-11-15n |