3m-2=3(m+1)-5

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Solution for 3m-2=3(m+1)-5 equation: 



3m-2=3(m+1)-5

We move all terms to the left:

3m-2-(3(m+1)-5)=0



We calculate terms in parentheses: -(3(m+1)-5), so:

3(m+1)-5

We multiply parentheses

3m+3-5

We add all the numbers together, and all the variables

3m-2

Back to the equation:

-(3m-2)



We get rid of parentheses

3m-3m+2-2=0

We add all the numbers together, and all the variables

=0

m=0/1

m=0

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