3m-2(m+19)=9m-3(9-m)

Solution for 3m-2(m+19)=9m-3(9-m) equation:

3m-2(m+19)=9m-3(9-m)

We move all terms to the left:

3m-2(m+19)-(9m-3(9-m))=0

We add all the numbers together, and all the variables

3m-2(m+19)-(9m-3(-1m+9))=0

We multiply parentheses

3m-2m-(9m-3(-1m+9))-38=0


We calculate terms in parentheses: -(9m-3(-1m+9)), so:

9m-3(-1m+9)

We multiply parentheses

9m+3m-27

We add all the numbers together, and all the variables

12m-27

Back to the equation:

-(12m-27)


We add all the numbers together, and all the variables

m-(12m-27)-38=0

We get rid of parentheses

m-12m+27-38=0

We add all the numbers together, and all the variables

-11m-11=0

We move all terms containing m to the left, all other terms to the right

-11m=11

m=11/-11

m=-1