3m+m+(m-2)=48

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Solution for 3m+m+(m-2)=48 equation: 



3m+m+(m-2)=48

We move all terms to the left:

3m+m+(m-2)-(48)=0

We add all the numbers together, and all the variables

4m+(m-2)-48=0

We get rid of parentheses

4m+m-2-48=0

We add all the numbers together, and all the variables

5m-50=0

We move all terms containing m to the left, all other terms to the right

5m=50

m=50/5

m=10

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