3m+6=m(m-2)

Solution for 3m+6=m(m-2) equation:

3m+6=m(m-2)

We move all terms to the left:

3m+6-(m(m-2))=0


We calculate terms in parentheses: -(m(m-2)), so:

m(m-2)

We multiply parentheses

m^2-2m

Back to the equation:

-(m^2-2m)


We get rid of parentheses

-m^2+3m+2m+6=0

We add all the numbers together, and all the variables

-1m^2+5m+6=0

a = -1; b = 5; c = +6;
Δ = b2-4ac
Δ = 52-4·(-1)·6
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-7}{2*-1}=\frac{-12}{-2}
=+6
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+7}{2*-1}=\frac{2}{-2}
=-1
$