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3m+5=3/2m-6
We move all terms to the left:
3m+5-(3/2m-6)=0
Domain of the equation: 2m-6)!=0We get rid of parentheses
m∈R
3m-3/2m+6+5=0
We multiply all the terms by the denominator
3m*2m+6*2m+5*2m-3=0
Wy multiply elements
6m^2+12m+10m-3=0
We add all the numbers together, and all the variables
6m^2+22m-3=0
a = 6; b = 22; c = -3;
Δ = b2-4ac
Δ = 222-4·6·(-3)
Δ = 556
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{556}=\sqrt{4*139}=\sqrt{4}*\sqrt{139}=2\sqrt{139}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-2\sqrt{139}}{2*6}=\frac{-22-2\sqrt{139}}{12} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+2\sqrt{139}}{2*6}=\frac{-22+2\sqrt{139}}{12} $
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