3m+2(m-4)=6-m

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Solution for 3m+2(m-4)=6-m equation: 



3m+2(m-4)=6-m

We move all terms to the left:

3m+2(m-4)-(6-m)=0

We add all the numbers together, and all the variables

3m+2(m-4)-(-1m+6)=0

We multiply parentheses

3m+2m-(-1m+6)-8=0

We get rid of parentheses

3m+2m+1m-6-8=0

We add all the numbers together, and all the variables

6m-14=0

We move all terms containing m to the left, all other terms to the right

6m=14

m=14/6

m=2+1/3

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