3m+1(m+5)-(m+2)(m-5)=2(m-5)(m+5)

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Solution for 3m+1(m+5)-(m+2)(m-5)=2(m-5)(m+5) equation: 



3m+1(m+5)-(m+2)(m-5)=2(m-5)(m+5)

We move all terms to the left:

3m+1(m+5)-(m+2)(m-5)-(2(m-5)(m+5))=0

We use the square of the difference formula

m^2+3m+1(m+5)-(m+2)(m-5)+25=0

We multiply parentheses ..

m^2-(+m^2-5m+2m-10)+3m+1(m+5)+25=0

We get rid of parentheses

m^2-m^2+5m-2m+3m+1(m+5)+10+25=0

We add all the numbers together, and all the variables

6m+1(m+5)+35=0

We move all terms containing m to the left, all other terms to the right

6m+1(m+5)=-35

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