3m+-10=2(4m-5)+15

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Solution for 3m+-10=2(4m-5)+15 equation: 



3m+-10=2(4m-5)+15

We move all terms to the left:

3m+-10-(2(4m-5)+15)=0

We add all the numbers together, and all the variables

3m-(2(4m-5)+15)=0



We calculate terms in parentheses: -(2(4m-5)+15), so:

2(4m-5)+15

We multiply parentheses

8m-10+15

We add all the numbers together, and all the variables

8m+5

Back to the equation:

-(8m+5)



We get rid of parentheses

3m-8m-5=0

We add all the numbers together, and all the variables

-5m-5=0

We move all terms containing m to the left, all other terms to the right

-5m=5

m=5/-5

m=-1

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