3m(m-10)=0

Solution for 3m(m-10)=0 equation:

3m(m-10)=0

We multiply parentheses

3m^2-30m=0

a = 3; b = -30; c = 0;
Δ = b2-4ac
Δ = -302-4·3·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-30}{2*3}=\frac{0}{6}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+30}{2*3}=\frac{60}{6}
=10
$