3m(7m+12)=(m-3)

Solution for 3m(7m+12)=(m-3) equation:

3m(7m+12)=(m-3)

We move all terms to the left:

3m(7m+12)-((m-3))=0

We multiply parentheses

21m^2+36m-((m-3))=0


We calculate terms in parentheses: -((m-3)), so:

(m-3)

We get rid of parentheses

m-3

Back to the equation:

-(m-3)


We get rid of parentheses

21m^2+36m-m+3=0

We add all the numbers together, and all the variables

21m^2+35m+3=0

a = 21; b = 35; c = +3;
Δ = b2-4ac
Δ = 352-4·21·3
Δ = 973
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{973}}{2*21}=\frac{-35-\sqrt{973}}{42}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{973}}{2*21}=\frac{-35+\sqrt{973}}{42}
$