3l+3(k+2)=9+3k

Solution for 3l+3(k+2)=9+3k equation:

Simplifying
3l + 3(k + 2) = 9 + 3k

Reorder the terms:
3l + 3(2 + k) = 9 + 3k
3l + (2 * 3 + k * 3) = 9 + 3k
3l + (6 + 3k) = 9 + 3k

Reorder the terms:
6 + 3k + 3l = 9 + 3k

Add '-3k' to each side of the equation.
6 + 3k + -3k + 3l = 9 + 3k + -3k

Combine like terms: 3k + -3k = 0
6 + 0 + 3l = 9 + 3k + -3k
6 + 3l = 9 + 3k + -3k

Combine like terms: 3k + -3k = 0
6 + 3l = 9 + 0
6 + 3l = 9

Solving
6 + 3l = 9

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 3l = 9 + -6

Combine like terms: 6 + -6 = 0
0 + 3l = 9 + -6
3l = 9 + -6

Combine like terms: 9 + -6 = 3
3l = 3

Divide each side by '3'.
l = 1

Simplifying
l = 1