3k=2(2k-1)

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Solution for 3k=2(2k-1) equation: 



3k=2(2k-1)

We move all terms to the left:

3k-(2(2k-1))=0



We calculate terms in parentheses: -(2(2k-1)), so:

2(2k-1)

We multiply parentheses

4k-2

Back to the equation:

-(4k-2)



We get rid of parentheses

3k-4k+2=0

We add all the numbers together, and all the variables

-1k+2=0

We move all terms containing k to the left, all other terms to the right

-k=-2

k=-2/-1

k=+2

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