3k=(-5k+4)/6

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Solution for 3k=(-5k+4)/6 equation: 



3k=(-5k+4)/6

We move all terms to the left:

3k-((-5k+4)/6)=0

We multiply all the terms by the denominator


3k*6)-((-5k+4)=0

Wy multiply elements

18k^2=0

a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{0}{36}=0$

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