3k2-8k-35=0

Solution for 3k2-8k-35=0 equation:

3k^2-8k-35=0

a = 3; b = -8; c = -35;
Δ = b2-4ac
Δ = -82-4·3·(-35)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-22}{2*3}=\frac{-14}{6}
=-2+1/3
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+22}{2*3}=\frac{30}{6}
=5
$