3k+5=2(k+1)=

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Solution for 3k+5=2(k+1)= equation: 



3k+5=2(k+1)=

We move all terms to the left:

3k+5-(2(k+1))=0



We calculate terms in parentheses: -(2(k+1)), so:

2(k+1)

We multiply parentheses

2k+2

Back to the equation:

-(2k+2)



We get rid of parentheses

3k-2k-2+5=0

We add all the numbers together, and all the variables

k+3=0

We move all terms containing k to the left, all other terms to the right

k=-3

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