3k+4=3(6k-10)+79

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Solution for 3k+4=3(6k-10)+79 equation: 



3k+4=3(6k-10)+79

We move all terms to the left:

3k+4-(3(6k-10)+79)=0



We calculate terms in parentheses: -(3(6k-10)+79), so:

3(6k-10)+79

We multiply parentheses

18k-30+79

We add all the numbers together, and all the variables

18k+49

Back to the equation:

-(18k+49)



We get rid of parentheses

3k-18k-49+4=0

We add all the numbers together, and all the variables

-15k-45=0

We move all terms containing k to the left, all other terms to the right

-15k=45

k=45/-15

k=-3

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