3k+1=1/2(2k-6+5k)

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Solution for 3k+1=1/2(2k-6+5k) equation: 



3k+1=1/2(2k-6+5k)

We move all terms to the left:

3k+1-(1/2(2k-6+5k))=0



Domain of the equation: 2(2k-6+5k))!=0

k∈R



We add all the numbers together, and all the variables

3k-(1/2(7k-6))+1=0

We multiply all the terms by the denominator


3k*2(7k-6))-(1+1*2(7k-6))=0

Wy multiply elements

6k^2(7+2k(7=0

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