3k(k-5)=-16

Solution for 3k(k-5)=-16 equation:

3k(k-5)=-16

We move all terms to the left:

3k(k-5)-(-16)=0

We add all the numbers together, and all the variables

3k(k-5)+16=0

We multiply parentheses

3k^2-15k+16=0

a = 3; b = -15; c = +16;
Δ = b2-4ac
Δ = -152-4·3·16
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{33}}{2*3}=\frac{15-\sqrt{33}}{6}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{33}}{2*3}=\frac{15+\sqrt{33}}{6}
$