3k(k+5)=2(3k-6)

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Solution for 3k(k+5)=2(3k-6) equation: 



3k(k+5)=2(3k-6)

We move all terms to the left:

3k(k+5)-(2(3k-6))=0

We multiply parentheses

3k^2+15k-(2(3k-6))=0



We calculate terms in parentheses: -(2(3k-6)), so:

2(3k-6)

We multiply parentheses

6k-12

Back to the equation:

-(6k-12)



We get rid of parentheses

3k^2+15k-6k+12=0

We add all the numbers together, and all the variables

3k^2+9k+12=0

a = 3; b = 9; c = +12;
Δ = b2-4ac
Δ = 92-4·3·12
Δ = -63
Delta is less than zero, so there is no solution for the equation

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