3j+6-8j=3(3j-5+12)

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Solution for 3j+6-8j=3(3j-5+12) equation: 



3j+6-8j=3(3j-5+12)

We move all terms to the left:

3j+6-8j-(3(3j-5+12))=0

We add all the numbers together, and all the variables

3j-8j-(3(3j+7))+6=0

We add all the numbers together, and all the variables

-5j-(3(3j+7))+6=0



We calculate terms in parentheses: -(3(3j+7)), so:

3(3j+7)

We multiply parentheses

9j+21

Back to the equation:

-(9j+21)



We get rid of parentheses

-5j-9j-21+6=0

We add all the numbers together, and all the variables

-14j-15=0

We move all terms containing j to the left, all other terms to the right

-14j=15

j=15/-14

j=-1+1/14

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