3i-6=2(i-2)

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Solution for 3i-6=2(i-2) equation: 



3i-6=2(i-2)

We move all terms to the left:

3i-6-(2(i-2))=0



We calculate terms in parentheses: -(2(i-2)), so:

2(i-2)

We multiply parentheses

2i-4

Back to the equation:

-(2i-4)



We get rid of parentheses

3i-2i+4-6=0

We add all the numbers together, and all the variables

i-2=0

We move all terms containing i to the left, all other terms to the right

i=2

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