3i(6-i)=0

Solution for 3i(6-i)=0 equation:

3i(6-i)=0

We add all the numbers together, and all the variables

3i(-1i+6)=0

We multiply parentheses

-3i^2+18i=0

a = -3; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·(-3)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*-3}=\frac{-36}{-6}
=+6
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*-3}=\frac{0}{-6}
=0
$