3g=36/g=12

Solution for 3g=36/g=12 equation:

3g=36/g=12

We move all terms to the left:

3g-(36/g)=0


Domain of the equation: g)!=0

g!=0/1

g!=0

g∈R


We add all the numbers together, and all the variables

3g-(+36/g)=0

We get rid of parentheses

3g-36/g=0

We multiply all the terms by the denominator


3g*g-36=0

Wy multiply elements

3g^2-36=0

a = 3; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·3·(-36)
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{3}}{2*3}=\frac{0-12\sqrt{3}}{6}
=-\frac{12\sqrt{3}}{6}
=-2\sqrt{3}
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{3}}{2*3}=\frac{0+12\sqrt{3}}{6}
=\frac{12\sqrt{3}}{6}
=2\sqrt{3}
$