3d-15=3(d-5)

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Solution for 3d-15=3(d-5) equation: 



3d-15=3(d-5)

We move all terms to the left:

3d-15-(3(d-5))=0



We calculate terms in parentheses: -(3(d-5)), so:

3(d-5)

We multiply parentheses

3d-15

Back to the equation:

-(3d-15)



We get rid of parentheses

3d-3d+15-15=0

We add all the numbers together, and all the variables

=0

d=0/1

d=0

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