3d+16=1d+72

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Solution for 3d+16=1d+72 equation: 



3d+16=1d+72

We move all terms to the left:

3d+16-(1d+72)=0

We add all the numbers together, and all the variables

3d-(d+72)+16=0

We get rid of parentheses

3d-d-72+16=0

We add all the numbers together, and all the variables

2d-56=0

We move all terms containing d to the left, all other terms to the right

2d=56

d=56/2

d=28

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