3cos(2x)sin(2y)=1

Solution for 3cos(2x)sin(2y)=1 equation:

Simplifying
3cos(2x) * sin(2y) = 1

Remove parenthesis around (2x)
3cos * 2x * sin(2y) = 1

Remove parenthesis around (2y)
3cos * 2x * ins * 2y = 1

Reorder the terms for easier multiplication:
3 * 2 * 2cos * x * ins * y = 1

Multiply 3 * 2
6 * 2cos * x * ins * y = 1

Multiply 6 * 2
12cos * x * ins * y = 1

Multiply cos * x
12cosx * ins * y = 1

Multiply cosx * ins
12cinos2x * y = 1

Multiply cinos2x * y
12cinos2xy = 1

Solving
12cinos2xy = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '12inos2xy'.
c = 0.08333333333i-1n-1o-1s-2x-1y-1

Simplifying
c = 0.08333333333i-1n-1o-1s-2x-1y-1