3cos(2x)=sin(x)+2

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Solution for 3cos(2x)=sin(x)+2 equation: 


Simplifying
3cos(2x) = sin(x) + 2

Remove parenthesis around (2x)
3cos * 2x = sin(x) + 2

Reorder the terms for easier multiplication:
3 * 2cos * x = sin(x) + 2

Multiply 3 * 2
6cos * x = sin(x) + 2

Multiply cos * x
6cosx = sin(x) + 2

Multiply ins * x
6cosx = insx + 2

Reorder the terms:
6cosx = 2 + insx

Solving
6cosx = 2 + insx

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '6osx'.
c = 0.3333333333o-1s-1x-1 + 0.1666666667ino-1

Simplifying
c = 0.3333333333o-1s-1x-1 + 0.1666666667ino-1

Reorder the terms:
c = 0.1666666667ino-1 + 0.3333333333o-1s-1x-1

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