3c=2(2c+5)=3

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Solution for 3c=2(2c+5)=3 equation: 



3c=2(2c+5)=3

We move all terms to the left:

3c-(2(2c+5))=0



We calculate terms in parentheses: -(2(2c+5)), so:

2(2c+5)

We multiply parentheses

4c+10

Back to the equation:

-(4c+10)



We get rid of parentheses

3c-4c-10=0

We add all the numbers together, and all the variables

-1c-10=0

We move all terms containing c to the left, all other terms to the right

-c=10

c=10/-1

c=-10

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