3c2-45c+42=0

Solution for 3c2-45c+42=0 equation:

3c^2-45c+42=0

a = 3; b = -45; c = +42;
Δ = b2-4ac
Δ = -452-4·3·42
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-39}{2*3}=\frac{6}{6}
=1
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+39}{2*3}=\frac{84}{6}
=14
$