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3c^2+4c+88=-6c
We move all terms to the left:
3c^2+4c+88-(-6c)=0
We get rid of parentheses
3c^2+4c+6c+88=0
We add all the numbers together, and all the variables
3c^2+10c+88=0
a = 3; b = 10; c = +88;
Δ = b2-4ac
Δ = 102-4·3·88
Δ = -956
Delta is less than zero, so there is no solution for the equation
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