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3c-8=3(c-4)+1
We move all terms to the left:
3c-8-(3(c-4)+1)=0
We calculate terms in parentheses: -(3(c-4)+1), so:We get rid of parentheses
3(c-4)+1
We multiply parentheses
3c-12+1
We add all the numbers together, and all the variables
3c-11
Back to the equation:
-(3c-11)
3c-3c+11-8=0
We add all the numbers together, and all the variables
3!=0
There is no solution for this equation
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