3c-8(2c+3)=-6(2c+5)

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Solution for 3c-8(2c+3)=-6(2c+5) equation: 



3c-8(2c+3)=-6(2c+5)

We move all terms to the left:

3c-8(2c+3)-(-6(2c+5))=0

We multiply parentheses

3c-16c-(-6(2c+5))-24=0



We calculate terms in parentheses: -(-6(2c+5)), so:

-6(2c+5)

We multiply parentheses

-12c-30

Back to the equation:

-(-12c-30)



We add all the numbers together, and all the variables

-13c-(-12c-30)-24=0

We get rid of parentheses

-13c+12c+30-24=0

We add all the numbers together, and all the variables

-1c+6=0

We move all terms containing c to the left, all other terms to the right

-c=-6

c=-6/-1

c=+6

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