3c-4bc+(-7b)+3(2bc-b)=0

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Solution for 3c-4bc+(-7b)+3(2bc-b)=0 equation:


Simplifying
3c + -4bc + (-7b) + 3(2bc + -1b) = 0

Reorder the terms:
3c + -4bc + (-7b) + 3(-1b + 2bc) = 0
3c + -4bc + (-7b) + (-1b * 3 + 2bc * 3) = 0
3c + -4bc + (-7b) + (-3b + 6bc) = 0

Reorder the terms:
(-7b) + -3b + -4bc + 6bc + 3c = 0

Combine like terms: (-7b) + -3b = -10b
-10b + -4bc + 6bc + 3c = 0

Combine like terms: -4bc + 6bc = 2bc
-10b + 2bc + 3c = 0

Solving
-10b + 2bc + 3c = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3c' to each side of the equation.
-10b + 2bc + 3c + -3c = 0 + -3c

Combine like terms: 3c + -3c = 0
-10b + 2bc + 0 = 0 + -3c
-10b + 2bc = 0 + -3c
Remove the zero:
-10b + 2bc = -3c

Combine like terms: -3c + 3c = 0
-10b + 2bc + 3c = 0

The solution to this equation could not be determined.

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