3c-3/c=4c

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Solution for 3c-3/c=4c equation:


D( c )

c = 0

c = 0

c = 0

c in (-oo:0) U (0:+oo)

3*c-(3/c) = 4*c // - 4*c

3*c-(4*c)-(3/c) = 0

3*c-4*c-3*c^-1 = 0

-1*c^1-3*c^-1 = 0

(-1*c^2-3*c^0)/(c^1) = 0 // * c^2

c^1*(-1*c^2-3*c^0) = 0

c^1

-c^2-3 = 0

-c^2-3 = 0

DELTA = 0^2-(-3*(-1)*4)

DELTA = -12

DELTA < 0

c in { }

c belongs to the empty set

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