3c-3+6c+2=-(3c+1)

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Solution for 3c-3+6c+2=-(3c+1) equation: 



3c-3+6c+2=-(3c+1)

We move all terms to the left:

3c-3+6c+2-(-(3c+1))=0

We add all the numbers together, and all the variables

9c-(-(3c+1))-1=0



We calculate terms in parentheses: -(-(3c+1)), so:

-(3c+1)

We get rid of parentheses

-3c-1

Back to the equation:

-(-3c-1)



We get rid of parentheses

9c+3c+1-1=0

We add all the numbers together, and all the variables

12c=0

c=0/12

c=0

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