3c+8+(-6c)+5=c+5+2c+6+-8c

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Solution for 3c+8+(-6c)+5=c+5+2c+6+-8c equation: 



3c+8+(-6c)+5=c+5+2c+6+-8c

We move all terms to the left:

3c+8+(-6c)+5-(c+5+2c+6+-8c)=0

We add all the numbers together, and all the variables

3c+(-6c)-(-5c)+8+5=0

We add all the numbers together, and all the variables

3c+(-6c)-(-5c)+13=0

We get rid of parentheses

3c-6c+5c+13=0

We add all the numbers together, and all the variables

2c+13=0

We move all terms containing c to the left, all other terms to the right

2c=-13

c=-13/2

c=-6+1/2

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