3c+28=8c-7

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Solution for 3c+28=8c-7 equation: 



3c+28=8c-7

We move all terms to the left:

3c+28-(8c-7)=0

We get rid of parentheses

3c-8c+7+28=0

We add all the numbers together, and all the variables

-5c+35=0

We move all terms containing c to the left, all other terms to the right

-5c=-35

c=-35/-5

c=+7

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