3c+2(c+2)=13-2c-5

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Solution for 3c+2(c+2)=13-2c-5 equation:


Simplifying
3c + 2(c + 2) = 13 + -2c + -5

Reorder the terms:
3c + 2(2 + c) = 13 + -2c + -5
3c + (2 * 2 + c * 2) = 13 + -2c + -5
3c + (4 + 2c) = 13 + -2c + -5

Reorder the terms:
4 + 3c + 2c = 13 + -2c + -5

Combine like terms: 3c + 2c = 5c
4 + 5c = 13 + -2c + -5

Reorder the terms:
4 + 5c = 13 + -5 + -2c

Combine like terms: 13 + -5 = 8
4 + 5c = 8 + -2c

Solving
4 + 5c = 8 + -2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '2c' to each side of the equation.
4 + 5c + 2c = 8 + -2c + 2c

Combine like terms: 5c + 2c = 7c
4 + 7c = 8 + -2c + 2c

Combine like terms: -2c + 2c = 0
4 + 7c = 8 + 0
4 + 7c = 8

Add '-4' to each side of the equation.
4 + -4 + 7c = 8 + -4

Combine like terms: 4 + -4 = 0
0 + 7c = 8 + -4
7c = 8 + -4

Combine like terms: 8 + -4 = 4
7c = 4

Divide each side by '7'.
c = 0.5714285714

Simplifying
c = 0.5714285714

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