3c+2(c+2)=13-(c-5)

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Solution for 3c+2(c+2)=13-(c-5) equation:


Simplifying
3c + 2(c + 2) = 13 + -1(c + -5)

Reorder the terms:
3c + 2(2 + c) = 13 + -1(c + -5)
3c + (2 * 2 + c * 2) = 13 + -1(c + -5)
3c + (4 + 2c) = 13 + -1(c + -5)

Reorder the terms:
4 + 3c + 2c = 13 + -1(c + -5)

Combine like terms: 3c + 2c = 5c
4 + 5c = 13 + -1(c + -5)

Reorder the terms:
4 + 5c = 13 + -1(-5 + c)
4 + 5c = 13 + (-5 * -1 + c * -1)
4 + 5c = 13 + (5 + -1c)

Combine like terms: 13 + 5 = 18
4 + 5c = 18 + -1c

Solving
4 + 5c = 18 + -1c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add 'c' to each side of the equation.
4 + 5c + c = 18 + -1c + c

Combine like terms: 5c + c = 6c
4 + 6c = 18 + -1c + c

Combine like terms: -1c + c = 0
4 + 6c = 18 + 0
4 + 6c = 18

Add '-4' to each side of the equation.
4 + -4 + 6c = 18 + -4

Combine like terms: 4 + -4 = 0
0 + 6c = 18 + -4
6c = 18 + -4

Combine like terms: 18 + -4 = 14
6c = 14

Divide each side by '6'.
c = 2.333333333

Simplifying
c = 2.333333333

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