3c+(c+4)=127

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Solution for 3c+(c+4)=127 equation: 



3c+(c+4)=127

We move all terms to the left:

3c+(c+4)-(127)=0

We get rid of parentheses

3c+c+4-127=0

We add all the numbers together, and all the variables

4c-123=0

We move all terms containing c to the left, all other terms to the right

4c=123

c=123/4

c=30+3/4

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