3c+(2c+8)=28

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Solution for 3c+(2c+8)=28 equation: 



3c+(2c+8)=28

We move all terms to the left:

3c+(2c+8)-(28)=0

We get rid of parentheses

3c+2c+8-28=0

We add all the numbers together, and all the variables

5c-20=0

We move all terms containing c to the left, all other terms to the right

5c=20

c=20/5

c=4

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