3b=bx/x=t

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Solution for 3b=bx/x=t equation: 


1*x^4-(2*x^3)+1*x^2+0*x+0 = 0

1*x^3-(1*x^2)-(1*x)+0 = 0

e^(7-(3*t))

e^(7-(2*t))

(0.4*s+1)*(0.9*s+1)*(9*s+1) = 0

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