3b=b+32

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Solution for 3b=b+32 equation: 



3b=b+32

We move all terms to the left:

3b-(b+32)=0

We get rid of parentheses

3b-b-32=0

We add all the numbers together, and all the variables

2b-32=0

We move all terms containing b to the left, all other terms to the right

2b=32

b=32/2

b=16

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